What is the inverse of y= 3/4 sqrt(x+2)-1 ?

The inverse of y= 3/4 sqrt(x+2)-1 is (16x^2+32x+16)/9-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of y= 3/4 sqrt(x+2)-1

inverse

y = \frac{3}{4} x + 2 - 1

\frac{16 x ^{2} + 32 x + 16}{9} - 2

Solution steps

y = \frac{3}{4} x + 2 - 1

Replace

x

with

y

x = \frac{3}{4} y + 2 - 1

Solve for

y, x = \frac{3}{4} y + 2 - 1

\frac{16 x ^{2} + 32 x + 16}{9} - 2

y = 1 - \frac{2 - x}{3}

f (- 35) = 3 x - 1

4 z

f (x) = 2 - \frac{2}{x}

f (x) = - x + 9

What is the inverse of y= 3/4 sqrt(x+2)-1 ?
The inverse of y= 3/4 sqrt(x+2)-1 is (16x^2+32x+16)/9-2