What is the inverse of f(x)=sqrt(1-3x^2) ?

The inverse of f(x)=sqrt(1-3x^2) is sqrt(-(x^2-1)/3),-sqrt(-(x^2-1)/3)

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inverse of f(x)=sqrt(1-3x^2)

inverse

f (x) = 1 - 3 x^{2}

- \frac{x ^{2} - 1}{3}, - - \frac{x ^{2} - 1}{3}

Solution steps

y = 1 - 3 x^{2}

Replace

x

with

y

x = 1 - 3 y^{2}

Solve for

y, x = 1 - 3 y^{2}

- \frac{x ^{2} - 1}{3}, - - \frac{x ^{2} - 1}{3}

f (x) = - x + 4

f (x) = 0.5 x^{2} - 7 x + 24.5

f (x) = 1 - \frac{1}{2} e^{- x}

f (x) = lo g_{5} (x - 6) - 7

What is the inverse of f(x)=sqrt(1-3x^2) ?
The inverse of f(x)=sqrt(1-3x^2) is sqrt(-(x^2-1)/3),-sqrt(-(x^2-1)/3)