What is the inverse of f(x)=(1-sqrt(x(1-x)+1))/x ?

The inverse of f(x)=(1-sqrt(x(1-x)+1))/x is -(-2x-1)/(x^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(1-sqrt(x(1-x)+1))/x

inverse

f (x) = \frac{1 - x ( 1 - x ) + 1}{x}

- \frac{- 2 x - 1}{x ^{2} + 1}

Solution steps

y = \frac{1 - x ( 1 - x ) + 1}{x}

Replace

x

with

y

x = \frac{1 - y ( 1 - y ) + 1}{y}

Solve for

y, x = \frac{1 - y ( 1 - y ) + 1}{y}

- \frac{- 2 x - 1}{x ^{2} + 1}

g (x) = \frac{x - 9}{4}

f (x) = 20 e^{(\frac{1}{1690}, \frac{1}{2})}

f (x) = \frac{4 x - 4}{x + 1}

\frac{5 ^{x}}{5 + 5 ^{x}}

\frac{x ^{3} + 5}{4}

What is the inverse of f(x)=(1-sqrt(x(1-x)+1))/x ?
The inverse of f(x)=(1-sqrt(x(1-x)+1))/x is -(-2x-1)/(x^2+1)