What is the inverse of f(x)=4x+8x^2 ?

The inverse of f(x)=4x+8x^2 is (-1+sqrt(2x+1))/4 ,-(sqrt(2x+1)+1)/4

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inverse of f(x)=4x+8x^2

inverse

f (x) = 4 x + 8 x^{2}

\frac{- 1 + 2 x + 1}{4}, - \frac{2 x + 1 + 1}{4}

Solution steps

y = 4 x + 8 x^{2}

Replace

x

with

y

x = 4 y + 8 y^{2}

Solve for

y, x = 4 y + 8 y^{2}

\frac{- 1 + 2 x + 1}{4}, - \frac{2 x + 1 + 1}{4}

f (x) = - 2^{(x - 2)} + 5

f (5) = 2 x + 1

f (x) = \frac{- 3 x + 9}{x + 7}

f (x) = - 5 x^{5} + 3

f (x) = 1650 - 150 y

What is the inverse of f(x)=4x+8x^2 ?
The inverse of f(x)=4x+8x^2 is (-1+sqrt(2x+1))/4 ,-(sqrt(2x+1)+1)/4