What is the inverse of f(x)=x^{(2)},x>0 ?

The inverse of f(x)=x^{(2)},x>0 is sqrt(x),-sqrt(x)

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inverse of f(x)=x^{(2)},x>0

inverse

f (x) = x^{(2)}, x > 0

x, - x

Solution steps

y = x^{2}

Replace

x

with

y

x = y^{2}

Solve for

y, x = y^{2}

x, - x

f (x) = 2 (x - 2)^{2} - 1.5

- 4 x^{2} - x - 2

f (x) = x^{2} - 5 x + 3

f (x) = \frac{3 x + 5}{5 x - 4}

f (x) = (2 x)^{- \frac{9}{7}}

What is the inverse of f(x)=x^{(2)},x>0 ?
The inverse of f(x)=x^{(2)},x>0 is sqrt(x),-sqrt(x)