What is the inverse of f(x)=sqrt(2/pi)sin(r) ?

The inverse of f(x)=sqrt(2/pi)sin(r) is arcsin((sqrt(2)sqrt(pi)r)/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=sqrt(2/pi)sin(r)

inverse

f (x) = \frac{2}{π} sin (r)

arcsin (\frac{2 π r}{2})

Solution steps

Solve for

sin (r), x = \frac{2}{π} sin (r)

sin (r) = \frac{2 π x}{2}

sin (a) = b \Rightarrow a = arcsin (b)

arcsin (\frac{2 π x}{2})

Substitute

x = r

arcsin (\frac{2 π r}{2})

arctan (e^{2 x})

f (x) = \frac{2 x + 8}{3 x - 6}

f (x) = - \frac{3}{5}

f (59) = x^{3} - 5

f (x) = \frac{4 x}{3}

What is the inverse of f(x)=sqrt(2/pi)sin(r) ?
The inverse of f(x)=sqrt(2/pi)sin(r) is arcsin((sqrt(2)sqrt(pi)r)/2)