What is the inverse of log_{3}(4^x+4) ?

The inverse of log_{3}(4^x+4) is (ln(3^x-4))/(2ln(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of log_{3}(4^x+4)

inverse

lo g_{3} (4^{x} + 4)

\frac{ln ( 3 ^{x} - 4 )}{2 ln ( 2 )}

Solution steps

y = lo g_{3} (4^{x} + 4)

Replace

x

with

y

x = lo g_{3} (4^{y} + 4)

Solve for

y, x = lo g_{3} (4^{y} + 4)

\frac{ln ( 3 ^{x} - 4 )}{2 ln ( 2 )}

f (x) = \frac{1}{4} \cdot 1 0^{x - 3} + 5

f (x) = \frac{1}{1 + y ^{3}}

f (x) = \frac{y + 4}{2 y - 5}

f (x) = 14 - \frac{( 1 + 10 )}{3}

- 3 x^{2} - 4 x + 4

What is the inverse of log_{3}(4^x+4) ?
The inverse of log_{3}(4^x+4) is (ln(3^x-4))/(2ln(2))