What is the inverse of f(x)=1+(x+2)^2 ?

The inverse of f(x)=1+(x+2)^2 is sqrt(x-1)-2,-sqrt(x-1)-2

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inverse of f(x)=1+(x+2)^2

inverse

f (x) = 1 + (x + 2)^{2}

x - 1 - 2, - x - 1 - 2

Solution steps

y = 1 + (x + 2)^{2}

Replace

x

with

y

x = 1 + (y + 2)^{2}

Solve for

y, x = 1 + (y + 2)^{2}

x - 1 - 2, - x - 1 - 2

f (x) = \frac{- 2 x - 1}{x - 2}

f (x) = e^{9 s i n (x)}

f (x) = \frac{- 5 x}{4} - 20

f (x) = x_{8}

3 \frac{x - 1}{3}

What is the inverse of f(x)=1+(x+2)^2 ?
The inverse of f(x)=1+(x+2)^2 is sqrt(x-1)-2,-sqrt(x-1)-2