What is the inverse of y=((-1)3^x)/(11111111)+12 ?

The inverse of y=((-1)3^x)/(11111111)+12 is (ln(133333332-x*11111111))/(ln(3))

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inverse of y=((-1)3^x)/(11111111)+12

inverse

y = \frac{( - 1 ) 3 ^{x}}{11111111} + 12

\frac{ln ( 133333332 - x \cdot 11111111 )}{ln ( 3 )}

Solution steps

y = \frac{( - 1 ) \cdot 3 ^{x}}{11111111} + 12

Replace

x

with

y

x = \frac{( - 1 ) \cdot 3 ^{y}}{11111111} + 12

Solve for

y, x = \frac{( - 1 ) 3 ^{y}}{11111111} + 12

\frac{ln ( 133333332 - x \cdot 11111111 )}{ln ( 3 )}

f (t) = 100 (2^{\frac{t}{3}})

f (x) = arcsin (- \frac{3}{2})

f (x) = 2^{x} + 7

\frac{1}{s ^{7}}

- 3 x^{7} + 6

What is the inverse of y=((-1)3^x)/(11111111)+12 ?
The inverse of y=((-1)3^x)/(11111111)+12 is (ln(133333332-x*11111111))/(ln(3))