What is the inverse of log_{2}(4-x^2) ?

The inverse of log_{2}(4-x^2) is sqrt(-2^x+4),-sqrt(-2^x+4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of log_{2}(4-x^2)

inverse

lo g_{2} (4 - x^{2})

- 2^{x} + 4, - - 2^{x} + 4

Solution steps

y = lo g_{2} (4 - x^{2})

Replace

x

with

y

x = lo g_{2} (4 - y^{2})

Solve for

y, x = lo g_{2} (4 - y^{2})

- 2^{x} + 4, - - 2^{x} + 4

f (x) = e^{- 5 x}

f (x) = 0.9443

f (x) = - b ln (x)

lo g_{8} (x - 8)

\frac{1 + x}{3}

What is the inverse of log_{2}(4-x^2) ?
The inverse of log_{2}(4-x^2) is sqrt(-2^x+4),-sqrt(-2^x+4)