What is the inverse of f(x)=(-2x+7)/(x^2) ?

The inverse of f(x)=(-2x+7)/(x^2) is (-1+sqrt(7x+1))/x ,-(sqrt(7x+1)+1)/x

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inverse of f(x)=(-2x+7)/(x^2)

inverse

f (x) = \frac{- 2 x + 7}{x ^{2}}

\frac{- 1 + 7 x + 1}{x}, - \frac{7 x + 1 + 1}{x}

Solution steps

y = \frac{- 2 x + 7}{x ^{2}}

Replace

x

with

y

x = \frac{- 2 y + 7}{y ^{2}}

Solve for

y, x = \frac{- 2 y + 7}{y ^{2}}

\frac{- 1 + 7 x + 1}{x}, - \frac{7 x + 1 + 1}{x}

f (x) = \frac{5}{2} x - \frac{5}{6}

f (x) = 2 (x + 3) - \frac{x}{3}

5 x^{11} + 6

f (x) = 2 x^{2} - 7 x + 11, x \geq 2

\frac{8 x}{7 x - 4}

What is the inverse of f(x)=(-2x+7)/(x^2) ?
The inverse of f(x)=(-2x+7)/(x^2) is (-1+sqrt(7x+1))/x ,-(sqrt(7x+1)+1)/x