What is the inverse of 8(18x-5)^2-2(18x-5) ?

The inverse of 8(18x-5)^2-2(18x-5) is (41+sqrt(8x+1))/(144),(41-sqrt(8x+1))/(144)

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inverse of 8(18x-5)^2-2(18x-5)

inverse

8 (18 x - 5)^{2} - 2 (18 x - 5)

\frac{41 + 8 x + 1}{144}, \frac{41 - 8 x + 1}{144}

Solution steps

y = 8 (18 x - 5)^{2} - 2 (18 x - 5)

Replace

x

with

y

x = 8 (18 y - 5)^{2} - 2 (18 y - 5)

Solve for

y, x = 8 (18 y - 5)^{2} - 2 (18 y - 5)

\frac{41 + 8 x + 1}{144}, \frac{41 - 8 x + 1}{144}

f (x) = \frac{ln ( x + 2 )}{2} - \frac{3}{4}

f (x) = 4 x^{7} - 1

f (x) = - (x + 1)^{2} + 25

11 - 5 x^{3}

\frac{7}{4 + x}

What is the inverse of 8(18x-5)^2-2(18x-5) ?
The inverse of 8(18x-5)^2-2(18x-5) is (41+sqrt(8x+1))/(144),(41-sqrt(8x+1))/(144)