What is the inverse of g(x)=(9(4x-9))/4+17 ?

The inverse of g(x)=(9(4x-9))/4+17 is (4x+13)/(36)

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inverse of g(x)=(9(4x-9))/4+17

inverse

g (x) = \frac{9 ( 4 x - 9 )}{4} + 17

\frac{4 x + 13}{36}

Solution steps

y = \frac{9 ( 4 x - 9 )}{4} + 17

Replace

x

with

y

x = \frac{9 ( 4 y - 9 )}{4} + 17

Solve for

y, x = \frac{9 ( 4 y - 9 )}{4} + 17

\frac{4 x + 13}{36}

y = 0.1591 x^{3.7053}

f (x) = 2 e^{x + 3} - 3

tan (\frac{3.5}{7.59})

f (x) = x - 5 + 10

\frac{8}{7 + x ^{2}}

What is the inverse of g(x)=(9(4x-9))/4+17 ?
The inverse of g(x)=(9(4x-9))/4+17 is (4x+13)/(36)