What is the inverse of f(x)=2\sqrt[5]{x}-2 ?

The inverse of f(x)=2\sqrt[5]{x}-2 is (x^5}{32}+(5x^4)/(16)+\frac{5x^3)/4+(5x^2)/2+(5x)/2+1

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inverse of f(x)=2\sqrt[5]{x}-2

inverse

\frac{x ^{5}}{32} + \frac{5 x ^{4}}{16} + \frac{5 x ^{3}}{4} + \frac{5 x ^{2}}{2} + \frac{5 x}{2} + 1

Solution steps

Replace

x

with

y

Solve for

\frac{x ^{5}}{32} + \frac{5 x ^{4}}{16} + \frac{5 x ^{3}}{4} + \frac{5 x ^{2}}{2} + \frac{5 x}{2} + 1

f (x) = 9.2452 e^{- 7.289 x}

f (x) = tan (\frac{x}{1 + x})

f (x) = \frac{9 + 10 x}{8}

f (x) = \frac{6 x}{x - 3}, x \neq = 3

y = 43 x + 2

What is the inverse of f(x)=2\sqrt[5]{x}-2 ?
The inverse of f(x)=2\sqrt[5]{x}-2 is (x^5}{32}+(5x^4)/(16)+\frac{5x^3)/4+(5x^2)/2+(5x)/2+1