What is the inverse of (2S+2)/(S^2+4) ?

The inverse of (2S+2)/(S^2+4) is (1+sqrt(-2S(2S-1)+1))/S ,(1-sqrt(-2S(2S-1)+1))/S

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of (2S+2)/(S^2+4)

inverse

\frac{2 S + 2}{S ^{2} + 4}

\frac{1 + - 2 S ( 2 S - 1 ) + 1}{S}, \frac{1 - - 2 S ( 2 S - 1 ) + 1}{S}

Solution steps

y = \frac{2 S + 2}{S ^{2} + 4}

Replace

S

with

y

S = \frac{2 y + 2}{y ^{2} + 4}

Solve for

y, S = \frac{2 y + 2}{y ^{2} + 4}

\frac{1 + - 2 S ( 2 S - 1 ) + 1}{S}, \frac{1 - - 2 S ( 2 S - 1 ) + 1}{S}

f (x) = tan (- \frac{3}{3})

f (x) = \frac{( b ^{2} + 1 )}{b}

f (x) = \frac{3 x + 8}{x - 7}

f (x) = 0.12 x + 50

f (x) = ln (x) ln (x)

What is the inverse of (2S+2)/(S^2+4) ?
The inverse of (2S+2)/(S^2+4) is (1+sqrt(-2S(2S-1)+1))/S ,(1-sqrt(-2S(2S-1)+1))/S