What is the inverse of f(x)=sqrt(((1-x))/(1+x)) ?

The inverse of f(x)=sqrt(((1-x))/(1+x)) is (1-x^2)/(x^2+1)

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inverse of f(x)=sqrt(((1-x))/(1+x))

inverse

f (x) = \frac{( 1 - x )}{1 + x}

\frac{1 - x ^{2}}{x ^{2} + 1}

Solution steps

y = \frac{1 - x}{1 + x}

Replace

x

with

y

x = \frac{1 - y}{1 + y}

Solve for

y, x = \frac{1 - y}{1 + y}

\frac{1 - x ^{2}}{x ^{2} + 1}

\frac{2 π}{3}

f (x) = \frac{- 9}{2} x + 5

f (x) = \frac{e ^{- x}}{1 + e ^{- x}}

f (x) = tan (\frac{3.14 x}{2}) + 3

f (x) = f (x) = 2 x^{5} + 7

What is the inverse of f(x)=sqrt(((1-x))/(1+x)) ?
The inverse of f(x)=sqrt(((1-x))/(1+x)) is (1-x^2)/(x^2+1)