What is the inverse of 3x^2-18x+25 ?

The inverse of 3x^2-18x+25 is (18+sqrt(12x+24))/6 ,(18-sqrt(12x+24))/6

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inverse of 3x^2-18x+25

inverse

3 x^{2} - 18 x + 25

\frac{18 + 12 x + 24}{6}, \frac{18 - 12 x + 24}{6}

Solution steps

y = 3 x^{2} - 18 x + 25

Replace

x

with

y

x = 3 y^{2} - 18 y + 25

Solve for

y, x = 3 y^{2} - 18 y + 25

\frac{18 + 12 x + 24}{6}, \frac{18 - 12 x + 24}{6}

f (x) = \frac{6 x + 13}{5 x - 12}

f (x) = 3^{2 x + 1} - 4

x - 11

f (x) = 60 - 4.9 x^{2}

\frac{1}{x ^{2} + 1}

What is the inverse of 3x^2-18x+25 ?
The inverse of 3x^2-18x+25 is (18+sqrt(12x+24))/6 ,(18-sqrt(12x+24))/6