What is the inverse of f(x)=sqrt(38-x^2) ?

The inverse of f(x)=sqrt(38-x^2) is sqrt(-x^2+38),-sqrt(-x^2+38)

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inverse of f(x)=sqrt(38-x^2)

inverse

f (x) = 38 - x^{2}

- x^{2} + 38, - - x^{2} + 38

Solution steps

y = 38 - x^{2}

Replace

x

with

y

x = 38 - y^{2}

Solve for

y, x = 38 - y^{2}

- x^{2} + 38, - - x^{2} + 38

f (x) = - \frac{3 - x}{4 + x}

f (x) = - \frac{( 3 x - 5 )}{x}

f (x) = lo g_{5} (x - 2) + 1

+ ln (x^{2} - 4)

\frac{2 x + 4}{3}

What is the inverse of f(x)=sqrt(38-x^2) ?
The inverse of f(x)=sqrt(38-x^2) is sqrt(-x^2+38),-sqrt(-x^2+38)