What is the critical y=(2x)/3+(x+1)^{2/3} ?

The critical y=(2x)/3+(x+1)^{2/3} is x=-2,x=-1

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critical y=(2x)/3+(x+1)^{2/3}

critical points

y = \frac{2 x}{3} + (x + 1)^{\frac{2}{3}}

x = - 2, x = - 1

Solution steps

\frac{2 x}{3} + (x + 1)^{\frac{2}{3}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = - 1

Identify critical points not in

f (x)

domain

Domain of

\frac{2 x}{3} + (x + 1)^{\frac{2}{3}} : - \infty < x < \infty

All critical points are in domain

x = - 2, x = - 1

(- 6, 1), (2, - 5)

f (x) = x^{3} - 75 x + 10

f (x) = \frac{9 x - 21}{15 x + 35}

f (x) = - (x - 6) (x + 6) (x + 3)

sec (2 x - 3 π)

What is the critical y=(2x)/3+(x+1)^{2/3} ?
The critical y=(2x)/3+(x+1)^{2/3} is x=-2,x=-1