What is the inverse of f(x)=-3x^2+1 ?

The inverse of f(x)=-3x^2+1 is sqrt(-(x-1)/3),-sqrt(-(x-1)/3)

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inverse of f(x)=-3x^2+1

inverse

f (x) = - 3 x^{2} + 1

- \frac{x - 1}{3}, - - \frac{x - 1}{3}

Solution steps

y = - 3 x^{2} + 1

Replace

x

with

y

x = - 3 y^{2} + 1

Solve for

y, x = - 3 y^{2} + 1

- \frac{x - 1}{3}, - - \frac{x - 1}{3}

2 \cdot ln (x^{3})

f (x) = x + 43 x - 2

f (x) = \frac{5}{2} x + \frac{5}{2}

f (x) = (- 5) - 7

32 - 5

What is the inverse of f(x)=-3x^2+1 ?
The inverse of f(x)=-3x^2+1 is sqrt(-(x-1)/3),-sqrt(-(x-1)/3)