What is the inverse of (x^4+8)^{-1} ?

The inverse of (x^4+8)^{-1} is \sqrt[4]{(1-8x)/x},-\sqrt[4]{(1-8x)/x}

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inverse of (x^4+8)^{-1}

inverse

(x^{4} + 8)^{- 1}

Solution steps

y = (x^{4} + 8)^{- 1}

Replace

x

with

y

x = (y^{4} + 8)^{- 1}

Solve for

y, x = (y^{4} + 8)^{- 1}

\frac{8 x - 3}{4 x - 1}

x - 25

y = - \frac{2}{3} (x + 2) (x - 8)

y = - 60 (x - 3)^{2} - 50

f (x) = 7 x + 8

What is the inverse of (x^4+8)^{-1} ?
The inverse of (x^4+8)^{-1} is \sqrt[4]{(1-8x)/x},-\sqrt[4]{(1-8x)/x}