What is the inverse of y=2(x-3)^2+4 ?

The inverse of y=2(x-3)^2+4 is sqrt((x-4)/2)+3,-sqrt((x-4)/2)+3

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inverse of y=2(x-3)^2+4

inverse

y = 2 (x - 3)^{2} + 4

\frac{x - 4}{2} + 3, - \frac{x - 4}{2} + 3

Solution steps

y = 2 (x - 3)^{2} + 4

Replace

x

with

y

x = 2 (y - 3)^{2} + 4

Solve for

y, x = 2 (y - 3)^{2} + 4

\frac{x - 4}{2} + 3, - \frac{x - 4}{2} + 3

\frac{3 x - 5}{2 x + 1}

f (x) = \frac{3 x - 7}{5 x + 2}

f (y) = 0

f (x) = \frac{( 7 5 x - 5 )}{6}

\frac{75 x}{85 - x}

What is the inverse of y=2(x-3)^2+4 ?
The inverse of y=2(x-3)^2+4 is sqrt((x-4)/2)+3,-sqrt((x-4)/2)+3