What is the inverse of (16a^4+16a)/(a^2+1-a) ?

The inverse of (16a^4+16a)/(a^2+1-a) is (-2+sqrt(a+4))/4 ,-(sqrt(a+4)+2)/4

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inverse of (16a^4+16a)/(a^2+1-a)

inverse

\frac{16 a ^{4} + 16 a}{a ^{2} + 1 - a}

\frac{- 2 + a + 4}{4}, - \frac{a + 4 + 2}{4}

Solution steps

y = \frac{16 a ^{4} + 16 a}{a ^{2} + 1 - a}

Replace

a

with

y

a = \frac{16 y ^{4} + 16 y}{y ^{2} + 1 - y}

Solve for

y, a = \frac{16 y ^{4} + 16 y}{y ^{2} + 1 - y}

\frac{- 2 + a + 4}{4}, - \frac{a + 4 + 2}{4}

y = ln (\frac{x}{x - 1})

f (x) = \frac{8 x - 7}{7 x + 3}

f (p) = p - 38

\frac{- x + 5}{4}

f (x) = 1.6 x + 1.9 (50 - x)

What is the inverse of (16a^4+16a)/(a^2+1-a) ?
The inverse of (16a^4+16a)/(a^2+1-a) is (-2+sqrt(a+4))/4 ,-(sqrt(a+4)+2)/4