What is the inverse of log_{10}(3-x^2) ?

The inverse of log_{10}(3-x^2) is sqrt(-10^x+3),-sqrt(-10^x+3)

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inverse of log_{10}(3-x^2)

inverse

lo g_{10} (3 - x^{2})

- 1 0^{x} + 3, - - 1 0^{x} + 3

Solution steps

y = lo g_{10} (3 - x^{2})

Replace

x

with

y

x = lo g_{10} (3 - y^{2})

Solve for

y, x = lo g_{10} (3 - y^{2})

- 1 0^{x} + 3, - - 1 0^{x} + 3

y = \frac{6 x + 1}{x - 2}

f (x) = 9 x^{3} - 2

f (x) = 9 x^{3} - 3

y = 6 x - 30

f (x) = \frac{7 x + 5}{x - 1}

What is the inverse of log_{10}(3-x^2) ?
The inverse of log_{10}(3-x^2) is sqrt(-10^x+3),-sqrt(-10^x+3)