What is the inverse of f(x)=(x^2+4x-5)/(x^2-7x+6) ?

The inverse of f(x)=(x^2+4x-5)/(x^2-7x+6) is (5+6x)/(x-1)

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inverse of f(x)=(x^2+4x-5)/(x^2-7x+6)

inverse

f (x) = \frac{x ^{2} + 4 x - 5}{x ^{2} - 7 x + 6}

\frac{5 + 6 x}{x - 1}

Solution steps

y = \frac{x ^{2} + 4 x - 5}{x ^{2} - 7 x + 6}

Replace

x

with

y

x = \frac{y ^{2} + 4 y - 5}{y ^{2} - 7 y + 6}

Solve for

y, x = \frac{y ^{2} + 4 y - 5}{y ^{2} - 7 y + 6}

\frac{5 + 6 x}{x - 1}

5 + 2 x

\frac{1}{2} ln (x^{2} - 2 x - 1)

\frac{1}{\frac{6}{5} x - 9}

f (x) = 3 - e^{4 - 2 y}

y = \frac{5 - 3 x}{2 x - 3}

What is the inverse of f(x)=(x^2+4x-5)/(x^2-7x+6) ?
The inverse of f(x)=(x^2+4x-5)/(x^2-7x+6) is (5+6x)/(x-1)