What is the inverse of f(x)=(\sqrt[3]{6^x})/5 ?

The inverse of f(x)=(\sqrt[3]{6^x})/5 is (3ln(x*5))/(ln(6))

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inverse of f(x)=(\sqrt[3]{6^x})/5

inverse

f (x) = \frac{3 6 ^{x}}{5}

\frac{3 ln ( x \cdot 5 )}{ln ( 6 )}

Solution steps

y = \frac{3 6 ^{x}}{5}

Replace

x

with

y

x = \frac{3 6 ^{y}}{5}

Solve for

y, x = \frac{3 6 ^{y}}{5}

\frac{3 ln ( x \cdot 5 )}{ln ( 6 )}

\frac{1}{a}

(x - 4)^{2} + 3

f (x) = 8 x^{2} - 4

(x - 4)^{2} + 7

f (x) = \frac{9 x + 6}{x + 8}

What is the inverse of f(x)=(\sqrt[3]{6^x})/5 ?
The inverse of f(x)=(\sqrt[3]{6^x})/5 is (3ln(x*5))/(ln(6))