What is the inverse of 100(1-t/(40))^2 ?

The inverse of 100(1-t/(40))^2 is -4sqrt(t)+40,4sqrt(t)+40

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inverse of 100(1-t/(40))^2

inverse

100 (1 - \frac{t}{40})^{2}

- 4 t + 40, 4 t + 40

Solution steps

y = 100 (1 - \frac{t}{40})^{2}

Replace

t

with

y

t = 100 (1 - \frac{y}{40})^{2}

Solve for

y, t = 100 (1 - \frac{y}{40})^{2}

- 4 t + 40, 4 t + 40

f (x) = 3 x + (- 2)

\frac{1}{10 y + 9}

f (x) = 4 + x

f (x) = 3 - lo g_{10} (1 + x^{2})

f (x) = 60 t + 1000

What is the inverse of 100(1-t/(40))^2 ?
The inverse of 100(1-t/(40))^2 is -4sqrt(t)+40,4sqrt(t)+40