What is the inverse of f(x)=0.9(0.1^{x-1}) ?

The inverse of f(x)=0.9(0.1^{x-1}) is (ln((x*10)/9))/(ln(0.1))+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=0.9(0.1^{x-1})

inverse

f (x) = 0.9 (0. 1^{x - 1})

\frac{ln ( \frac{x \cdot 10}{9} )}{ln ( 0.1 )} + 1

Solution steps

y = 0.9 \cdot 0. 1^{x - 1}

Replace

x

with

y

x = 0.9 \cdot 0. 1^{y - 1}

Solve for

y, x = 0.90. 1^{y - 1}

\frac{ln ( \frac{x \cdot 10}{9} )}{ln ( 0.1 )} + 1

f (x) = x^{2} + 2 x - 3, x \geq 1

f (x) = 4 x^{2} + 10, x \geq 0

x + 14

x + 17

y = \frac{7 x}{1 - 2 x}

What is the inverse of f(x)=0.9(0.1^{x-1}) ?
The inverse of f(x)=0.9(0.1^{x-1}) is (ln((x*10)/9))/(ln(0.1))+1