What is the inverse of g(x)=4x^2-2 ?

The inverse of g(x)=4x^2-2 is (sqrt(x+2))/2 ,-(sqrt(x+2))/2

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inverse of g(x)=4x^2-2

inverse

g (x) = 4 x^{2} - 2

\frac{x + 2}{2}, - \frac{x + 2}{2}

Solution steps

y = 4 x^{2} - 2

Replace

x

with

y

x = 4 y^{2} - 2

Solve for

y, x = 4 y^{2} - 2

\frac{x + 2}{2}, - \frac{x + 2}{2}

x = e^{y}

f (x) = 2.8 sin (0.5 x - 1.5) + 12

y = 2 x - 12

\frac{x - 2}{x - 4}

f (x) = 6 arcsin (x^{5})

What is the inverse of g(x)=4x^2-2 ?
The inverse of g(x)=4x^2-2 is (sqrt(x+2))/2 ,-(sqrt(x+2))/2