What is the inverse of f(x)=((2x-1))/((x+2)) ?

The inverse of f(x)=((2x-1))/((x+2)) is (-1-2x)/(x-2)

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inverse of f(x)=((2x-1))/((x+2))

inverse

f (x) = \frac{( 2 x - 1 )}{( x + 2 )}

\frac{- 1 - 2 x}{x - 2}

Solution steps

y = \frac{2 x - 1}{x + 2}

Replace

x

with

y

x = \frac{2 y - 1}{y + 2}

Solve for

y, x = \frac{2 y - 1}{y + 2}

\frac{- 1 - 2 x}{x - 2}

\frac{x + 5}{x - 6}

f (x) = 3 x + 11

(4 (- 2) - 1)^{(- 1)}

g (x) = \frac{- 4}{x}

f (x) = 2 - \frac{1}{x - 1}

What is the inverse of f(x)=((2x-1))/((x+2)) ?
The inverse of f(x)=((2x-1))/((x+2)) is (-1-2x)/(x-2)