What is the inverse of f(x)=(2/(s^2))-(2/(s^2)) ?

The inverse of f(x)=(2/(s^2))-(2/(s^2)) is None

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inverse of f(x)=(2/(s^2))-(2/(s^2))

inverse

f (x) = (\frac{2}{s ^{2}}) - (\frac{2}{s ^{2}})

None

Solution steps

x = \frac{2}{s ^{2}} - \frac{2}{s ^{2}}

Replace

s

with

x

s = \frac{2}{x ^{2}} - \frac{2}{x ^{2}}

Solve for

x, s = \frac{2}{x ^{2}} - \frac{2}{x ^{2}}

Therefore, there are no inverse functions for

\frac{2}{s ^{2}} - \frac{2}{s ^{2}}

None

- \frac{4}{x - 1}

f (x) = \frac{x ^{2} + 3}{3 + x}

f (x) = 32 + y \frac{9}{5}

y = \frac{2 - x}{2 x - 1}

What is the inverse of f(x)=(2/(s^2))-(2/(s^2)) ?
The inverse of f(x)=(2/(s^2))-(2/(s^2)) is None