What is the inverse of sqrt(((3x-1))/(2x+1)) ?

The inverse of sqrt(((3x-1))/(2x+1)) is (-1-x^2)/(2x^2-3)

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inverse of sqrt(((3x-1))/(2x+1))

inverse

\frac{( 3 x - 1 )}{2 x + 1}

\frac{- 1 - x ^{2}}{2 x ^{2} - 3}

Solution steps

y = \frac{3 x - 1}{2 x + 1}

Replace

x

with

y

x = \frac{3 y - 1}{2 y + 1}

Solve for

y, x = \frac{3 y - 1}{2 y + 1}

\frac{- 1 - x ^{2}}{2 x ^{2} - 3}

y = \frac{2 x + 3}{x}

\frac{- 6 x + 13}{2 x - 7}

y^{2} - 6 y + 3

2 X^{3} + 5

f (49) = (x + 3)^{2}

What is the inverse of sqrt(((3x-1))/(2x+1)) ?
The inverse of sqrt(((3x-1))/(2x+1)) is (-1-x^2)/(2x^2-3)