What is the inverse of f(x)=log_{1/2}(2y)+3 ?

The inverse of f(x)=log_{1/2}(2y)+3 is 1/(2^{y-2)}

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inverse of f(x)=log_{1/2}(2y)+3

inverse

f (x) = lo g_{\frac{1}{2}} (2 y) + 3

\frac{1}{2 ^{y - 2}}

Solution steps

x = lo g_{\frac{1}{2}} (2 y) + 3

Replace

y

with

x

y = lo g_{\frac{1}{2}} (2 x) + 3

Solve for

x, y = lo g_{\frac{1}{2}} (2 x) + 3

\frac{1}{2 ^{y - 2}}

f (x) = \frac{( 4 x - 7 )}{2 x + 3}

f (x) = 0.5 x - 5

f (x) = (1 + x) x

f (x) = \frac{( x + 1 )}{x ( x - 1 )}

f (4) = 9 x - 13

What is the inverse of f(x)=log_{1/2}(2y)+3 ?
The inverse of f(x)=log_{1/2}(2y)+3 is 1/(2^{y-2)}