What is the inverse of 3x^{1/3}+2 ?

The inverse of 3x^{1/3}+2 is (x^3}{27}-\frac{2x^2)/9+(4x)/9-8/27

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inverse of 3x^{1/3}+2

inverse

3 x^{\frac{1}{3}} + 2

\frac{x ^{3}}{27} - \frac{2 x ^{2}}{9} + \frac{4 x}{9} - \frac{8}{27}

Solution steps

y = 3 x^{\frac{1}{3}} + 2

Replace

x

with

y

x = 3 y^{\frac{1}{3}} + 2

Solve for

y, x = 3 y^{\frac{1}{3}} + 2

\frac{x ^{3}}{27} - \frac{2 x ^{2}}{9} + \frac{4 x}{9} - \frac{8}{27}

f (x) = \frac{x}{5 x - 1}

f (x) = e^{- x} + 6

f (x) = \frac{1}{3} (x - 2)

f (x) = 0.025 x^{3}

lo g_{4} (- 85)

What is the inverse of 3x^{1/3}+2 ?
The inverse of 3x^{1/3}+2 is (x^3}{27}-\frac{2x^2)/9+(4x)/9-8/27