What is the extreme 3x^4-4x^3-12x^2+1 ?

The extreme 3x^4-4x^3-12x^2+1 is Minimum(-1,-4),Maximum(0,1),Minimum(2,-31)

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extreme 3x^4-4x^3-12x^2+1

extreme points

3 x^{4} - 4 x^{3} - 12 x^{2} + 1

Minimum (- 1, - 4), Maximum (0, 1), Minimum (2, - 31)

Solution steps

f^{'} (x) = 12 x^{3} - 12 x^{2} - 24 x

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 1

into

3 x^{4} - 4 x^{3} - 12 x^{2} + 1 : - 4

Minimum (- 1, - 4)

Plug

x = 0

into

3 x^{4} - 4 x^{3} - 12 x^{2} + 1 : 1

Maximum (0, 1)

Plug

x = 2

into

3 x^{4} - 4 x^{3} - 12 x^{2} + 1 : - 31

Minimum (2, - 31)

Minimum (- 1, - 4), Maximum (0, 1), Minimum (2, - 31)

\frac{2 x}{x - 1}

f (x) = 4 tan (x + \frac{π}{20})

x^{\frac{1}{3}} (x + 4)

y = 3 x - 1, (3, 2)

f (x) = \frac{- 9 - 7 x}{3}

What is the extreme 3x^4-4x^3-12x^2+1 ?
The extreme 3x^4-4x^3-12x^2+1 is Minimum(-1,-4),Maximum(0,1),Minimum(2,-31)