What is the inverse of f(x)=19x^2-17 ?

The inverse of f(x)=19x^2-17 is sqrt((x+17)/(19)),-sqrt((x+17)/(19))

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inverse of f(x)=19x^2-17

inverse

f (x) = 19 x^{2} - 17

\frac{x + 17}{19}, - \frac{x + 17}{19}

Solution steps

y = 19 x^{2} - 17

Replace

x

with

y

x = 19 y^{2} - 17

Solve for

y, x = 19 y^{2} - 17

\frac{x + 17}{19}, - \frac{x + 17}{19}

f (x) = 8 x - 2 + 5

f (x) = \frac{6}{1 - x}

(21) (21)

\frac{y ^{2}}{4}

f (x) = \frac{1}{4 x + 2}

What is the inverse of f(x)=19x^2-17 ?
The inverse of f(x)=19x^2-17 is sqrt((x+17)/(19)),-sqrt((x+17)/(19))