What is the inverse of f(x)=2(x-1)^3+6 ?

The inverse of f(x)=2(x-1)^3+6 is \sqrt[3]{(x-6)/2}+1

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inverse of f(x)=2(x-1)^3+6

inverse

f (x) = 2 (x - 1)^{3} + 6

Solution steps

y = 2 (x - 1)^{3} + 6

Replace

x

with

y

x = 2 (y - 1)^{3} + 6

Solve for

y, x = 2 (y - 1)^{3} + 6

f (x) = 2 (x - 1)^{3} + 3

2 + 3

\frac{- \frac{3}{5} x + 15}{2}

f (x) = 2 + \frac{4 x}{3}

f (y) = 2 y - 2 y^{2}

What is the inverse of f(x)=2(x-1)^3+6 ?
The inverse of f(x)=2(x-1)^3+6 is \sqrt[3]{(x-6)/2}+1