What is the inverse of-3/(s^2-6s+13) ?

The inverse of-3/(s^2-6s+13) is (3s+sqrt(s(-4s-3)))/s ,(3s-sqrt(s(-4s-3)))/s

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inverse of-3/(s^2-6s+13)

inverse

- \frac{3}{s ^{2} - 6 s + 13}

\frac{3 s + s ( - 4 s - 3 )}{s}, \frac{3 s - s ( - 4 s - 3 )}{s}

Solution steps

y = - \frac{3}{s ^{2} - 6 s + 13}

Replace

s

with

y

s = - \frac{3}{y ^{2} - 6 y + 13}

Solve for

y, s = - \frac{3}{y ^{2} - 6 y + 13}

\frac{3 s + s ( - 4 s - 3 )}{s}, \frac{3 s - s ( - 4 s - 3 )}{s}

\frac{2 x ^{2} + 1}{3 x - 2}

3 x^{2} - 27

lo g_{10} (x - 2) - 4

f (x) = 13.5 - 5 x

f (x) = 7^{5^{x}}

What is the inverse of-3/(s^2-6s+13) ?
The inverse of-3/(s^2-6s+13) is (3s+sqrt(s(-4s-3)))/s ,(3s-sqrt(s(-4s-3)))/s