What is the inverse of f(x)=(15x+1)^2 ?

The inverse of f(x)=(15x+1)^2 is (sqrt(x)-1)/(15),(-sqrt(x)-1)/(15)

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inverse of f(x)=(15x+1)^2

inverse

f (x) = (15 x + 1)^{2}

\frac{x - 1}{15}, \frac{- x - 1}{15}

Solution steps

y = (15 x + 1)^{2}

Replace

x

with

y

x = (15 y + 1)^{2}

Solve for

y, x = (15 y + 1)^{2}

\frac{x - 1}{15}, \frac{- x - 1}{15}

f (x) = \frac{4 ^{x}}{9}

\frac{x}{9 x - 2}

\frac{x ^{2}}{3}

f (x) = ln (3.2 x + 2.7)

y = 3 - x

What is the inverse of f(x)=(15x+1)^2 ?
The inverse of f(x)=(15x+1)^2 is (sqrt(x)-1)/(15),(-sqrt(x)-1)/(15)