What is the inverse of 3/(9s^2+12s+13) ?

The inverse of 3/(9s^2+12s+13) is (-12s+sqrt(-324s^2+108s))/(18s),(-12s-sqrt(-324s^2+108s))/(18s)

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inverse of 3/(9s^2+12s+13)

inverse

\frac{3}{9 s ^{2} + 12 s + 13}

\frac{- 12 s + - 324 s ^{2} + 108 s}{18 s}, \frac{- 12 s - - 324 s ^{2} + 108 s}{18 s}

Solution steps

y = \frac{3}{9 s ^{2} + 12 s + 13}

Replace

s

with

y

s = \frac{3}{9 y ^{2} + 12 y + 13}

Solve for

y, s = \frac{3}{9 y ^{2} + 12 y + 13}

\frac{- 12 s + - 324 s ^{2} + 108 s}{18 s}, \frac{- 12 s - - 324 s ^{2} + 108 s}{18 s}

f (x) = \frac{x}{2} - 7

f (x) = 2 (\frac{1}{x - 5})

7^{0.5}

y = 1 3^{x}

What is the inverse of 3/(9s^2+12s+13) ?
The inverse of 3/(9s^2+12s+13) is (-12s+sqrt(-324s^2+108s))/(18s),(-12s-sqrt(-324s^2+108s))/(18s)