What is the inverse of 1/((s^2+5^2)(s^2+7^2)) ?

The inverse of 1/((s^2+5^2)(s^2+7^2)) is

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inverse of 1/((s^2+5^2)(s^2+7^2))

inverse

\frac{1}{( s ^{2} + 5 ^{2} ) ( s ^{2} + 7 ^{2} )}

\frac{- 37 s + s ( 144 s + 1 )}{s}, - \frac{- 37 s + s ( 144 s + 1 )}{s}, - \frac{37 s + s ( 144 s + 1 )}{s}, - - \frac{37 s + s ( 144 s + 1 )}{s}

Solution steps

y = \frac{1}{( s ^{2} + 5 ^{2} ) ( s ^{2} + 7 ^{2} )}

Replace

s

with

y

s = \frac{1}{( y ^{2} + 5 ^{2} ) ( y ^{2} + 7 ^{2} )}

Solve for

y, s = \frac{1}{( y ^{2} + 5 ^{2} ) ( y ^{2} + 7 ^{2} )}

\frac{- 37 s + s ( 144 s + 1 )}{s}, - \frac{- 37 s + s ( 144 s + 1 )}{s}, - \frac{37 s + s ( 144 s + 1 )}{s}, - - \frac{37 s + s ( 144 s + 1 )}{s}

y = \frac{5}{11} x + 10

+ 3 - 4 sin (\frac{2}{3} (x - 1))

f (x) = (1 - \frac{1}{0.15 \cdot 10 + 1})

y = \frac{3 x}{2} + 3

f (x) = \frac{3}{2 + x}

What is the inverse of 1/((s^2+5^2)(s^2+7^2)) ?
The inverse of 1/((s^2+5^2)(s^2+7^2)) is