What is the inverse of f(x)=-1/(3(\frac{1){3x})} ?

The inverse of f(x)=-1/(3(\frac{1){3x})} is -x

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inverse of f(x)=-1/(3(\frac{1){3x})}

inverse

f (x) = - \frac{1}{3 ( \frac{1}{3 x} )}

- x

Solution steps

y = - \frac{1}{3 \cdot \frac{1}{3 x}}

Replace

x

with

y

x = - \frac{1}{3 \cdot \frac{1}{3 y}}

Solve for

y, x = - \frac{1}{3 \frac{1}{3 y}}

- x

sin (0.925)

f (x) = 14 x + 2

f (x) = \frac{( 2 x + 7 )}{10 x - 12}

\frac{( x + 8 )}{2}

2 - 8 x^{3}

What is the inverse of f(x)=-1/(3(\frac{1){3x})} ?
The inverse of f(x)=-1/(3(\frac{1){3x})} is -x