What is the inverse of y=log_{2}(log_{10}(x)) ?

The inverse of y=log_{2}(log_{10}(x)) is 10^{2^x}

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inverse of y=log_{2}(log_{10}(x))

inverse

y = lo g_{2} (lo g_{10} (x))

1 0^{2^{x}}

Solution steps

y = lo g_{2} (lo g_{10} (x))

Replace

x

with

y

x = lo g_{2} (lo g_{10} (y))

Solve for

y, x = lo g_{2} (lo g_{10} (y))

1 0^{2^{x}}

- \frac{1}{x - 3} + 2

f (x) = 4 + ln (x - 2)

\frac{( x + 8 )}{6}

f (x) = \frac{2}{3} x - 9

1 x^{3} + 3

What is the inverse of y=log_{2}(log_{10}(x)) ?
The inverse of y=log_{2}(log_{10}(x)) is 10^{2^x}