What is the inverse of (6x)/(36-x^2) ?

The inverse of (6x)/(36-x^2) is -(3(sqrt(4x^2+1)+1))/x ,-(3(-sqrt(4x^2+1)+1))/x

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inverse of (6x)/(36-x^2)

inverse

\frac{6 x}{36 - x ^{2}}

- \frac{3 ( 4 x ^{2} + 1 + 1 )}{x}, - \frac{3 ( - 4 x ^{2} + 1 + 1 )}{x}

Solution steps

y = \frac{6 x}{36 - x ^{2}}

Replace

x

with

y

x = \frac{6 y}{36 - y ^{2}}

Solve for

y, x = \frac{6 y}{36 - y ^{2}}

- \frac{3 ( 4 x ^{2} + 1 + 1 )}{x}, - \frac{3 ( - 4 x ^{2} + 1 + 1 )}{x}

lo g_{10} (x + 5)

(\frac{1}{4})^{1 - x^{2}}

f (x) = 2 x - 5 = 2

sin (0.8353)

f (x) = \frac{( x + 2 )}{1 - 2 x}

What is the inverse of (6x)/(36-x^2) ?
The inverse of (6x)/(36-x^2) is -(3(sqrt(4x^2+1)+1))/x ,-(3(-sqrt(4x^2+1)+1))/x