What is the inverse of f(x)=-10t^2+60t+10 ?

The inverse of f(x)=-10t^2+60t+10 is -(-60+sqrt(-40t+4000))/(20),-(-60-sqrt(-40t+4000))/(20)

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inverse of f(x)=-10t^2+60t+10

inverse

f (x) = - 10 t^{2} + 60 t + 10

- \frac{- 60 + - 40 t + 4000}{20}, - \frac{- 60 - - 40 t + 4000}{20}

Solution steps

x = - 10 t^{2} + 60 t + 10

Replace

t

with

x

t = - 10 x^{2} + 60 x + 10

Solve for

x, t = - 10 x^{2} + 60 x + 10

- \frac{- 60 + - 40 t + 4000}{20}, - \frac{- 60 - - 40 t + 4000}{20}

f (x) = 3 lo g_{10} (x - 1)

arccos (\frac{11}{x})

f (x) = \frac{( - 3 x - 3 )}{x - 2}

f (x) = - \frac{1}{3} x

tan (x) 0.5

What is the inverse of f(x)=-10t^2+60t+10 ?
The inverse of f(x)=-10t^2+60t+10 is -(-60+sqrt(-40t+4000))/(20),-(-60-sqrt(-40t+4000))/(20)