What is the inverse of f(x)=-1/((4t-7)^2) ?

The inverse of f(x)=-1/((4t-7)^2) is (sqrt(-1/t)+7)/4 ,(-sqrt(-1/t)+7)/4

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inverse of f(x)=-1/((4t-7)^2)

inverse

f (x) = - \frac{1}{( 4 t - 7 ) ^{2}}

\frac{- \frac{1}{t} + 7}{4}, \frac{- - \frac{1}{t} + 7}{4}

Solution steps

x = - \frac{1}{( 4 t - 7 ) ^{2}}

Replace

t

with

x

t = - \frac{1}{( 4 x - 7 ) ^{2}}

Solve for

x, t = - \frac{1}{( 4 x - 7 ) ^{2}}

\frac{- \frac{1}{t} + 7}{4}, \frac{- - \frac{1}{t} + 7}{4}

\frac{2 s + 1}{3 s ^{2} + 27}

f (x) = 0.95905

3 + 7 - 3 x^{2}

y = x^{2} - 1

f (x) = 2^{5 x}

What is the inverse of f(x)=-1/((4t-7)^2) ?
The inverse of f(x)=-1/((4t-7)^2) is (sqrt(-1/t)+7)/4 ,(-sqrt(-1/t)+7)/4