inverse f(x)=4-3cos(3x-x/3)

الحلّ

inverse

f (x) = 4 - 3 cos (3 x - \frac{x}{3})

\frac{3 arccos ( - \frac{x - 4}{3} )}{8}

خطوات الحلّ

y = 4 - 3 cos (3 x - \frac{x}{3}), cos (3 x - \frac{x}{3})

حلّ لـ

cos (3 x - \frac{x}{3}) = - \frac{y - 4}{3}

cos (a) = b \Rightarrow a = arccos (b)

3 x - \frac{x}{3} = arccos (- \frac{y - 4}{3})

3 x - \frac{x}{3} = arccos (- \frac{y - 4}{3}), x

حلّ لـ

\frac{3 arccos ( - \frac{y - 4}{3} )}{8}

y = x

استبدل

\frac{3 arccos ( - \frac{x - 4}{3} )}{8}

f (x) = \frac{( 3 + 2 x )}{( x - 7 )}

f (x) = e^{\frac{x + 1}{x - 1}}

\frac{10 x + 5}{2 x - 10}

f (x) = g (x) = x^{2} - 5 x - 6