What is the inverse of f(x)=x+(x^2)/2 ?

The inverse of f(x)=x+(x^2)/2 is -1+sqrt(2x+1),-sqrt(2x+1)-1

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inverse of f(x)=x+(x^2)/2

inverse

f (x) = x + \frac{x ^{2}}{2}

- 1 + 2 x + 1, - 2 x + 1 - 1

Solution steps

y = x + \frac{x ^{2}}{2}

Replace

x

with

y

x = y + \frac{y ^{2}}{2}

Solve for

y, x = y + \frac{y ^{2}}{2}

- 1 + 2 x + 1, - 2 x + 1 - 1

f (x) = 16 x^{2}, x \geq 0

f (x) = \frac{x + 6}{5 - x}

f (x) = \frac{3}{x} - 7

f (x) = \frac{12}{7 - 6 x}

f (x) = \frac{1}{2} x + \frac{1}{4}

What is the inverse of f(x)=x+(x^2)/2 ?
The inverse of f(x)=x+(x^2)/2 is -1+sqrt(2x+1),-sqrt(2x+1)-1