What is the inverse of 1/4*10^{x-3}+5 ?

The inverse of 1/4*10^{x-3}+5 is (ln(4x-20))/(ln(10))+3

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inverse of 1/4*10^{x-3}+5

inverse

\frac{1}{4} \cdot 1 0^{x - 3} + 5

\frac{ln ( 4 x - 20 )}{ln ( 10 )} + 3

Solution steps

y = \frac{1}{4} \cdot 1 0^{x - 3} + 5

Replace

x

with

y

x = \frac{1}{4} \cdot 1 0^{y - 3} + 5

Solve for

y, x = \frac{1}{4} \cdot 1 0^{y - 3} + 5

\frac{ln ( 4 x - 20 )}{ln ( 10 )} + 3

f (x) = \frac{1}{3} π x^{3}

f (x) = (\frac{3}{4})^{x}

\frac{5}{3 x - 7}

f (x) = - \frac{3}{- x - 1} + 1

f (x) = \frac{7 - x}{9}

What is the inverse of 1/4*10^{x-3}+5 ?
The inverse of 1/4*10^{x-3}+5 is (ln(4x-20))/(ln(10))+3