What is the inverse of f(x)=((4-3x))/(4x-2) ?

The inverse of f(x)=((4-3x))/(4x-2) is (4+2x)/(4x+3)

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inverse of f(x)=((4-3x))/(4x-2)

inverse

f (x) = \frac{( 4 - 3 x )}{4 x - 2}

\frac{4 + 2 x}{4 x + 3}

Solution steps

y = \frac{4 - 3 x}{4 x - 2}

Replace

x

with

y

x = \frac{4 - 3 y}{4 y - 2}

Solve for

y, x = \frac{4 - 3 y}{4 y - 2}

\frac{4 + 2 x}{4 x + 3}

g (x) = 6^{x}

f (x) = 1 - lo g_{3} (x + 1)

f (x) = \frac{7 - x}{5}

- 1 + 4 x

lo g_{2} (x + 2)

What is the inverse of f(x)=((4-3x))/(4x-2) ?
The inverse of f(x)=((4-3x))/(4x-2) is (4+2x)/(4x+3)